A question about xdebug_break [Resolved]

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yuyuki
Posts: 5
Joined: Mon Jan 05, 2009 11:39 pm

A question about xdebug_break [Resolved]

Post by yuyuki »

Hello everybody,

I Use Rapid PHP 2008 (The last Version)

I would like to debug a web site from a third part php server "Easy PHP" (last version)

I've already confirgure php.ini with xdebug and I see it with php_info.

My question is :

how can I use Ā« xdebug_break() Ā» for call a debugger and retrieve the context.

When I write a simple doc like : <?php xdebug_break(); ?>, firefox display the page normally and does not call rapid php for debugging?

Maybe I need a DBGp proxy.

Could you help me?

thank for your help


Solution
1) I've download a plugin for firefox for easily starting and stoping xdebug session.
I've configure parameter same as purpose on this plugin. So the value of xdebug.idkey = «default» in php.ini

2) In RapidPHP, I've change the session name to «default» in setting of debugger and I click on the «Run» button

3) If I display a php page with xdebug_break() instruction, RapidPhp has been called and I retrieve all context variables

I hope this explanation help other people
Last edited by yuyuki on Wed Jan 07, 2009 3:31 pm, edited 2 times in total.
yuyuki
Posts: 5
Joined: Mon Jan 05, 2009 11:39 pm

Re: A question about xdebug_break

Post by yuyuki »

I've found not enough explanation at this url http://xdebug.org/docs/remote

Code: Select all

bool xdebug_break( )
Emits a breakpoint to the debug client.

This function makes the debugger break on the specific line as if a normal file/line breakpoint was set on this line. 
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